-333.33x+1500x^2-2250=0

Solution for -333.33x+1500x^2-2250=0 equation:

-333.33x+1500x^2-2250=0

a = 1500; b = -333.33; c = -2250;
Δ = b2-4ac
Δ = -333.332-4·1500·(-2250)
Δ = 13611108.8889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-333.33)-\sqrt{13611108.8889}}{2*1500}=\frac{333.33-\sqrt{13611108.8889}}{3000}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-333.33)+\sqrt{13611108.8889}}{2*1500}=\frac{333.33+\sqrt{13611108.8889}}{3000}
$